Print rotor count distribution
A program that prints the rotorcount distribution for a database of
molecules. It uses OEIsRotor functor to determine
if a bond is freely rotatable. Use the
OEGetRotatableBondCount function to get a more precise count
of rotatable bonds in a molecule.
Example
prompt > rotorcount.py input.oeb.gz
Code
Download code
#!/usr/bin/env python
# (C) 2022 Cadence Design Systems, Inc. (Cadence)
# All rights reserved.
# TERMS FOR USE OF SAMPLE CODE The software below ("Sample Code") is
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# subject to these terms. Cadence claims no rights to Customer's
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# THE SAMPLE CODE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND,
# EXPRESS OR IMPLIED. OPENEYE DISCLAIMS ALL WARRANTIES, INCLUDING, BUT
# NOT LIMITED TO, WARRANTIES OF MERCHANTABILITY, FITNESS FOR A
# PARTICULAR PURPOSE AND NONINFRINGEMENT. In no event shall Cadence be
# liable for any damages or liability in connection with the Sample Code
# or its use.
#############################################################################
# Counts the number of rotatable bonds in the input compound file and
# outputs the maximum number of rotamers and the rotomer distribution
#############################################################################
import sys
from openeye import oechem
def CountRotors(ifs):
rotcounts = []
for mol in ifs.GetOEMols():
nrots = oechem.OECount(mol, oechem.OEIsRotor())
while nrots >= len(rotcounts):
rotcounts.append(0)
rotcounts[nrots] += 1
print("Max rotors:", len(rotcounts) - 1)
print("Rotorcount distribution:")
for rots, numrot in enumerate(rotcounts):
print("\t%d:\t%d" % (rots, numrot))
def main(argv=[__name__]):
if len(argv) != 2:
oechem.OEThrow.Usage("%s <infile>" % argv[0])
ifs = oechem.oemolistream()
if not ifs.open(argv[1]):
oechem.OEThrow.Fatal("Unable to open %s for reading" % argv[1])
CountRotors(ifs)
if __name__ == "__main__":
sys.exit(main(sys.argv))
See also
OEIsRotor functor
OEGetRotatableBondCountfunction